Question

solve the equation - 7y-1/4-1/3(2y-1-y/2)=10/3​

Answer 1

Hello A@tma!!

$7y - \frac{1}{4} - \frac{1}{3} (2y - 1 - \frac{y}{2}) = \frac{10}{3} \\7y - \frac{1}{4} - \frac{2y}{3} + \frac{1}{3} + \frac{y}{6} = \frac{10}{3} \\ 7y - \frac{2y}{3} + \frac{y}{6} = \frac{10}{3} + \frac{1}{4} - \frac{1}{3} \ \\ \frac{42y - 4y + y}{6} = \frac{40 + 3 - 4}{12} \\ \frac{39y}{6} = \frac{39}{12} \\ 39y = \frac{39}{12} \times 6 \\ 39y = \frac{39}{2} \\ y = \frac{39}{2} \times \frac{1}{39} \\ \\ y = \frac{1}{2}$

Hope it helps....✌✌