Math, asked by challapavani1988, 7 months ago

solve the equation 8x^3 - 6x + 1=0​

Answers

Answered by sharmavedansh02
0

Step-by-step explanation:

8x*3-6x+1=0

24x-6x= -1

18x= -1

x = -1/18

Answered by udayJi
0

Answer:

hence its cubic polynomial so there must be 3 zeroes,

we can use various methods to solve

let's use Factorisation

8x^3-6x+1=0

2x (4x-3) +1 (-6x+1) = 0

so,

(2x+1) (4x-3) (-6x+1) = 0

so here we get three equation now substitute each with zero to get root

2x+1 = 0

X= -1/2

4x-3=0

X= 3/4

-6x+1=0

X= 1/6

We can check this by substituting in main equation.

..........Thank you!.........

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