Solve the equation 8x+4y=7 and 6x-8y=41 by substitution method
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Our equation is
8x+4y=7 ...........1equation
6x-8y=41.............2equation
8x+4y=7
4y=7-8x
Y=7-8x/4
We get value of y
By putting value of y in equation 2
6x-8y=41
6x-8(7-8x/4)=41
6x-14-16x=41
-10x=41+14
X=5.5
By putting the value of x in equation 1
8x+4y=7
8(5.5)+4y=7
44+4y=7
4y=7-44
Y=37/4
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