Math, asked by rahulbabani, 1 year ago

solve the equation 9x2 -15x+6=0 by the method of completing the square

Answers

Answered by sumayahkabeer
122

ax-by+c=0

1. Divide all terms by a so that a=1

2. Take c to the other side

3. Add (b/2)^2 to both the sides. (Be careful about the sign of 'b' and also do not forget to remove 'bx'.)

4. Remove the square from both sides

5. Now simplify to find x.

Hope this helps.... ☺️

Attachments:
Answered by VishalSharma01
40

Answer:

Step-by-step explanation:

Solution :-

Here, we have

⇒ 9x² - 15x + 6 = 0

Dividing equation by 9

x² - 15/9x + 6/9 = 0

⇒ x² - 5/3x + 2/3 = 0

Shifting constant term on RHS

x² - 5/3x = - 2/3

Adding square of half of coefficient of x on both sides

x² - 2(5/6)x + (5/6)² = (5/6)² - 2/3

⇒ (x - 5/6)² = 25/36 - 2/3

⇒ (x - 5/6)² = 25 - 24/36

⇒ (x - 5/6)² = 1/36

Taking square root of both sides

x - 5/6 = ± 1/6

⇒ x = 5/6 ± 1/6

⇒ x = 5/6 + 1/6 = 1 or 5/6 - 1/6 = 4/6 = 2/3

x = 1, 2/3

Hence, the roots of the equation are 1 and 2/3.

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