Math, asked by jdivyam779, 8 months ago

solve the equation
9y-7/5y-3
where value of y is 15/7​

Answers

Answered by suraj245670
2

Answer:

Y/2y-15 = 7/9

9y = 14y-105

14y-9y = 105

5y = 105

y = 105/5 = 21

so,

y should be 21

Answered by Anonymous
0

{\huge {\underline {\bf {\pink {Answer}}}}}

9y-7/5y-3

Putting y = \frac {15}{7}

= 9×(\frac {15}{7}) - \frac {7}{5} × \frac {15}{7} -3

 = \frac {135}{7}- 3 - 3

 = \frac {135}{7}- 0

 = \frac {135}{7}

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