Math, asked by sareermir757, 10 months ago

Solve the equation.

A number consists of two digits whose sum is equal to 8. When 18 is added to the number, the digit interchange their places. Find the number

Answers

Answered by nvarshininatarajan
0

Answer:

35

Step-by-step explanation:

Let us assume that one of the digit of the two digit number is X, then problem the other number will be (8 - X)

From problem we get that, if we add 27 to the number the digits get interchanged and also since the number is a two digit number then X will in tens place (7 - X) will be in ones place.

So the equation we get

10X + (8 - X) + 18 = 10(8 - X) + X

10X + 8 - X + 18 = 80 -10X + X

9X + 26 = 80 - 9X

9X + 9X = 80 - 26

18X = 54

X = 54/18

X = 3,

So the digit in tens place = 3 the digit in ones place is (8 - 3 = 5) , then the number is 35 and when 18 is added the result is 53, the digits interchange their position in the new number.

Ans: 35

Answered by kaursandeep112
1

Answer:

35

Step-by-step explanation:

Let one of the number be x

And other no. be 8-x

10x+(8-x)+18 = 10 (8-x)+x

=10x+8-x+18 = 80-10x+x

=9x+26 = 80-26

=18x = 54

= x = 54/18

=x=3

one no.= x=3

other no.=8-x

=8-3

=5

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