Question

solve the equation adx² -(ab-cd)x =bc​

Answer 1

Answer:

(a) The given equation can be re written as

Σax-Σ a  

2

 = 2Σbc

or  xΣ a = Σ a  

2

  +  2Σbc

or    xΣa = (Σ a)  

2

   or   Σa (x - Σa) = 0

∴     x=Σa=a+b+c,

provided a + b + c  



​  

= 0

(b) L.H.S. =  

x−a−b

x  

2

−ax−bx+ab

​  

=  

x−a−b

x(x−a−b)

​  

+  

x−a−b

ab

​  

=x+  

x−a−b

ab

​  

 

∴    

x−a−b

ab

​  

=  

x−c−d

cd

​  

 

or    ab (x-c + d) = cd (x- a-b)

ac(b-a) + bd(a - c)

or  x=  

ab−cd

ac(b−d)+bd(a−c)

Step-by-step explanation:

Answer 2

Step-by-step explanation:

open the brackets, rearrange and then factorise