Question

Solve the equation and check your solution:​

Answer 1

Answer:

Given

(19−3y)

(1−9y)

=

8

5

/* Doing Cross multiplication , we get */

\implies 8(1-9y) = 5(19-3y)⟹8(1−9y)=5(19−3y)

\implies 8 - 72y = 95 - 15y⟹8−72y=95−15y

/* Add bothsides by 15y , we get */

\implies 8 - 72y + 15y = 95 - 15y + 15y⟹8−72y+15y=95−15y+15y

\implies 8 - 57y = 95⟹8−57y=95

/* Subtract bothsides by 8 , we get */

\implies 8 - 57y - 8 = 95 - 8⟹8−57y−8=95−8

\implies - 57y = 87⟹−57y=87

\implies y = \frac{87}{-57}⟹y=

−57

87

Therefore.,

\red { Value \: of \: y } \green {= -\frac{87}{57}}Valueofy=−

57

87

•••♪

Answer 2

Answer:

$\frac{1 - 9y}{19 - 3y} = \frac{5}{8} \\ by \: cross \: multiplication \: \\ 8(1 - 9y) = 5(19 - 3y) \\ 8 - 72y = 95 - 15y \\ 8 - 95 = - 15y + 72y \\ - 87 = 57y \\ y = \frac{ - 87}{57}$

By putting the value of y into the question you will verify

It is the correct answer of your question

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