solve the equation and find p and q
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First cross multiply 3/P and 3/Q you will get 3Q+3P/PQ=1
3Q+3P/PQ=1 (multiply PQ×1 that is cross multiply)
You will get 3Q+3P=PQ
Take 3 as common and send it to the other side that is
P+Q=PQ/3 where or consider P+Q= 1/3 and now solve PQ=3
Solve it by quadratic formula with Pand Q that is,
x^2-(P+Q)x+PQ substitue P+Q and PQ values that we have got,
x^2-(1/3)x+3=0 from this you will get an equation 3x^2-x+9=0
Substitue a=3,b=-1 and c=9
In -b±√b^2-4ac/2a you will get roots are imaginary
3Q+3P/PQ=1 (multiply PQ×1 that is cross multiply)
You will get 3Q+3P=PQ
Take 3 as common and send it to the other side that is
P+Q=PQ/3 where or consider P+Q= 1/3 and now solve PQ=3
Solve it by quadratic formula with Pand Q that is,
x^2-(P+Q)x+PQ substitue P+Q and PQ values that we have got,
x^2-(1/3)x+3=0 from this you will get an equation 3x^2-x+9=0
Substitue a=3,b=-1 and c=9
In -b±√b^2-4ac/2a you will get roots are imaginary
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