Solve the equation and I will mark you as brainlest:
0.25( 4f-3 ) = 0.05( 10f-9 )
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1
Answer:
Given,0.25(4f−3)=0.05(10f−9)
⟹
100
25
(4f−3)=
100
5
(10f−9)
⟹25(4f−3)=5(10f−9). [Onmultiplyingbothsidesby100]
⟹5(4f−3)=10f−9[] Ondividingbothsidesby5]
⟹20f−15=10f−9
⟹20f−10f=−9+15. [Transposing10ftoLHSand−15toRHS]
⟹10f=6
⟹f=
10
6
or
5
3
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