Question

solve the equation and verify the solution : 15(y-4)-2(y-9)+5(y+6)=0​

Answer 1

$\sf\huge\bold{Solution}$

$\sf \longmapsto15(y - 4) - 2(y - 9) + 5(y + 6) = 0$

$\sf \longmapsto15y - 60 - 2y + 18 + 5y + 30 = 0$

$\sf \longmapsto18y - 30 + 18 = 0$

$\sf \longmapsto18y - 12 = 0$

$\sf \longmapsto18y = 12$

$\sf \longmapsto \: y = \dfrac{12}{18} = \dfrac{2}{3}$

$\sf \: y = \dfrac{2}{3}$

Now , check

$\sf \longmapsto15 \times \dfrac{2}{3} - 60 - 2 \times \dfrac{2}{3} + 18 + 5 \times \dfrac{2}{3} + 30$

$\sf \longmapsto10 - 60 - \dfrac{4}{3} + 18 + \dfrac{10}{3} + 30$

$\sf \longmapsto \dfrac{30 - 180 - 4 + 54 + 10 + 90}{3}$

$\sf \longmapsto \dfrac{ - 150 + 50 + 100}{3}$

$\sf \longmapsto \dfrac{ - 150 + 150}{3} = \dfrac{0}{3} = 0$

Answer 2

15(y-4)-2(y-9)+5(y+6)=0

$\huge\mathcal{\fcolorbox{cyan}{black}{\pink{ᴀɴsᴡᴇʀ࿐}}}$

15(y−4)−2(y−9)+5(y+6)=0

⇒15y−60−2y+18+5y+30=0

⇒18y−12=0

⇒18y=12

⇒y= 12/18= 2/3

∴y= 2/3