Question

solve the equation and verify your answer:
Y-(7-8y) by 9y - (3+4y) =11/7​

Answer 1

Answer:

y-(7-8y) by 9y-(3+4y) = 11/7

y-7+8y by 9y-3-4y = 11/7

9y-7 by 5y-3 = 11/7

7(9y-7) = 11(5y-3) (cross multiplying)

63y-49 = 55y-33

63y-55y = 49-33

8y = 16

y = 16/8 =2

Step-by-step explanation:

verification :

substituting the value of y in given equation

2-(7-8x2) by 9x2-(3+4x2) = 11/7

2-(7-16) by 18-(3+8) = 11/7

2-(-9) by 18-(11) = 11/7

2+9 by 18-11 = 11/7

11 by 7 = 11/7

11/7 = 11/7

LHS = RHS

Hence verified

Answer 2

Given Equation -

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• $\sf \dfrac{y-(7-8y)}{9y - (3+4y) } = \dfrac{11}{7}$

Solution -

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We will solve the equation by simplifying LHS and RHS, Simplifying LHS and RHS helps to solve more easily.

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$\dashrightarrow \sf \dfrac{y-(7-8y)}{9y - (3+4y) } = \dfrac{11}{7}$

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$\dashrightarrow \sf \dfrac{y-7 + 8y}{9y - 3 - 4y} = \dfrac{11}{7}$

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$\dashrightarrow \sf \dfrac{9y-7 }{5y - 3 } = \dfrac{11}{7}$

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$\dashrightarrow \sf7(9y-7 ) = 11(5y - 3)$

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$\dashrightarrow \sf63y-49 = 55y - 33$

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$\dashrightarrow \sf63y-55y= 49 - 33$

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$\dashrightarrow \sf8y= 16$

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$\dashrightarrow \sf y= \dfrac{16}{8}$

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$\dashrightarrow \sf y= 2$

Hence,

• Value of y is 2.

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Verification -

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$\dashrightarrow \sf \dfrac{y-(7-8y)}{9y - (3+4y) } = \dfrac{11}{7}$

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$\dashrightarrow \sf \dfrac{2-(7-8(2))}{9(2) - (3+4(2) } = \dfrac{11}{7}$

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$\dashrightarrow \sf \dfrac{2-(7-16)}{18- (3+8) } = \dfrac{11}{7}$

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$\dashrightarrow \sf \dfrac{2-7+16}{18- 3+8 } = \dfrac{11}{7}$

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$\dashrightarrow \sf \dfrac{-5+16}{18- 11 } = \dfrac{11}{7}$

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$\dashrightarrow \sf \dfrac{11}{7} = \dfrac{11}{7}$

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Hence,

• As LHS is equal to RHS, Answer is verified.

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