Question

Solve the equation ax^2 +2abx =0,a,b notequal 0. Using factorisation ​

Answer 1

Answer:

ax*(ax+2b)

Step-by-step explanation:

(ax)^2+2abx;

Now take 'ax' common ;. \\from (ax)^2 and 2abx

Then,

ax•(ax+2b) \\ Answer

Hope it will help you