solve the equation ax+b=0,where a and b are rationals and a is not 0
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8
Step-by-step explanation:
Assuming that A,B are integers then x2+Ax+B has a rational root implies the root, r, takes the form r=pq where p divides B and q divies 1 (the leading coefficient). This means q=±1.
Answered by
7
ax+b=0
ax= -b
x= -b/a
now if if A and B are rational and A is not equal to zero .
then,
X belongs to a negative rational number
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