Question

solve the equation below​

Answer 1

Answer:

V1=126.4 cm³

T1=27°C = 300K

P1=760 mm

V2=?

T2= 273K

P2= 760 mm

(P1V1)/T1=(P2V2)/T2

V2 = (760 * 126.4 * 273)/(300 * 760)

V2= 115.02 cm³

126.4cc weighs = 0.23g

1cc weigh = 0.23/126.4

115.02cc weighs = (0.23*115.02)/126.4

                           = 26.45/126.4

                           = 0.21g

22.4 L of liquid at STP weighs = 0.21g

so molecular mass of liquid = 0.21g

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