Question

Solve the equation by completing square method : x² + 4x + 3 = 0 
class 10th ​

Answer 1

Answer:

Given equation is x² + 4x + 3 = 0

Here we don't need to divide the whole polynomial by the coefficient as it's already 1.

Now to complete square, add 4 to both sides

→ x² + 4x + 3 + 4 = 4

→ x² + 2.2.x + 2² + 3 = 4

x² + 2.2.x + 2² = ( x + 2 )²

→ ( x + 2 )² + 3 = 4

→ ( x + 2 )² + 3 = 4

→ ( x + 2 )² = 4 - 3 = 1

→ x + 2 = ± √1 = ± 1

If x + 2 = - 1

x = 2 - 1 = 1

If x + 2 = 1

x = - 2 + 1 = - 1

Hence the required values of x are 1 and - 1

Here,

When x = 1, numeric value of equation is 1² + 4(1) + 3 = 8 ≠ 0

Hence there's only one value of x satisfying the condition i.e., - 1

Answer 2

Step-by-step explanation:

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