solve the equation by cross multiplication 2(ax-by) +a+ 4b =0 and 2 (bx+ay) + b - 4a=0
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Given pair of linear equations are: 2(ax - by) + (a + 4b) =0 2(bx + ay) + (b - 4a) =0The
above equations can be written as:2ax – 2by + (a + 4b) = 0 2bx + 2ay + (b – 4a) = 0 The pair of linear equations can be written using cross multiplication method as,
above equations can be written as:2ax – 2by + (a + 4b) = 0 2bx + 2ay + (b – 4a) = 0 The pair of linear equations can be written using cross multiplication method as,
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2 (ax-by) +a+4b=0 and 2 (bx+ay) +b-4a = 0
2ax -2 by +ay +4b +{(2bx + 2ay)} +b-4a = 0
2ax - 2bybx + ay + 4b +2bx+2ay+b-4a = 0
LAS is not equal to RHS
2ax -2 by +ay +4b +{(2bx + 2ay)} +b-4a = 0
2ax - 2bybx + ay + 4b +2bx+2ay+b-4a = 0
LAS is not equal to RHS
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