Question

Solve the equation by factorisation method (x-3)² = 64​

Answer 1

Answer:

x= -5 or 11

Step-by-step explanation:

$(x-3)^{2} -64 =0$

$(x-3)^{2}-8^{2} =0$

$(x-3+8)(x-3-8)=0$

(x+5)(x-11)=0

if x+5=0 then x=-5

if x-11 =0 then x=11

another method

$x^{2} +9 -6x =64$

$x^{2}-6x -55 =0$

$x^{2} - 11x +5x -55 =0$

x(x-11)+5(x-11)=0

(x-11)(x+5)=0

if x+5=0 then x=-5

if x-11 =0 then x=11

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Answer 2

Answer:

(11-3)^2 = 64

step by step explanation:

(x-3)^2 = 64

(x-3) = √64

(x-3) = 8

(x) = 11

therefore, (11-3)^2 = 8^2 = 64

hole it helps!

Thank you!