solve the equation by factorizaion method 2x/x-3 + 1/2x+3 + 3x+9/(x-3)(2x+3) =0
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Refer to the attachment!!!!!!!!!
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Answer:
x = -1 ________(1).
x = -3/2 _______(2).
Solutions:
2x/x - 3 + 1/2x + 3 + 3x + 9/(x - 3)(2x + 3) = 0
2x/x - 3 + 1/2x + 3 + 3x + 9/2x^2 + 3x - 6x - 9 = 0
2x/x - 3 + 1/2x + 3 + 3x + 9/2x^2 - 3x - 9 = 0
2x(2x + 3) + 1(x + 3)/(x - 3)(2x + 3) + 3x + 9/2x^2 - 3x - 9 = 0
4x^2 + 6x + x - 3/(2x^2 - 3x - 9) + 3x + 9/2x^2 - 3x - 9 = 0
4x^2 +6x + x - 3/(2x^2 - 3x - 9 = 0
4x^2 + 7x - 3 + 3x + 9/2x^2 - 3x - 9 = 0
4x^2 + 10x + 6/2x^2 - 3x - 9 = 0
4x^2 + 10x + 6 = 0(2x^2 - 2 - 3x - 9)
4x^2 + 10x + 6 = 0
4x^2 + 4x + 6x + 6 = 0
4x(x + 1) + 6(x + 1) = 0
( x + 1)0
x = -1
(4x + 6) = 0
4x = -6
x = -3/2
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