Question

Solve the equation by factorizaion method 2x/x-3 + 1/2x+3 + 3x+9/(x-3)(2x+3) =0

Answer 1

Answer:x=-1 and x=-3/2

Step-by-step explanation:

2x/x-3+1/2x+3+3x+9/(x-3)(2x+3)=0

2x/x-3+1/2x+3+3x+9/2x^2+3x-6x-9=0

2x/x-3+1/2x+3+3x+9/2x^2-3x-9=0

2x(2x+3)+1(x-3)/(x-3)(2x+3)+3x+9/2x^2-3x-9=0

4x^2+6x+x-3/(2x^2-3x-9)+3x+9/2x^2-3x-9=0

4x^2+7x-3+3x+9/2x^2-3x-9=0

4x^2+10x+6/2x^2-3x-9=0

4x^2+10x+6=0(2x^2-3x-9)

4x^2+10x+6=0

4x^2+4x+6x+6=0

4x(x+1)+6(x+1)=0

(X+1)=0. (4x+6)=0

X=-1. 4x=-6

x=-6/4

x=-3/2

Answer 2

Refer to the attachment!!!!!!