Question

solve the equation by introducing a new variable (x-2) ² (x²-4x) -12 = 0​

Answer 1

$x {}^{2} - 2 {}^{2} \times x {}^{2} -4x = 12 \\ x {}^{2} \times - 3x = 12 + 4 \\ - 3x {}^{3} = 16 \\ x {}^{3} = 16 \div - 3 \\ x ^3 = - 5.33 \\ x = - 1.8$