Question

Solve the equation by quadratic formula: 4x2-4a2x+(a4-b4)=0

Answer 1

4x²-4a²x+(a⁴-b⁴)=0

a=4
b=-4a²
c=a⁴-b⁴
D=

${b}^{2} - 4ac$
(-4a²)²-4×4×(a⁴-b⁴)
16a⁴-16a⁴+16b⁴
D=16b⁴

x=-b±√D/2a
=-(-4a²)±4a²/2×4
=4a²±4a²/8

x=4a²+4a²/8
=8a²/8
=a²

x=4a²-4a²/8
=0/8
=0

the roots of the given quadratic equations is a² & 0......

HOPE this helps you...

Answer 2

Answer:

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