solve the equation by substitution method..
1. 3x-y = 3
9x - 3y = 9
2. 0.5x + 0.8y = 3.4
0.6x - 0.3y = 0.3
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2
there is no need to solve it
2: solved see in pic
2: solved see in pic
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Answered by
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1.
3x-y=3 -----(1)
9x-3y=9------(2)
x= 3+y / 3
9 ( 3+y / 3) = 9
27+9y /3 = 9
27 +9y = 9*3
9y = 27-27
9y =0
y=0/9
y=0
(put value of y in 1st equation)
3x-y=3
3x-0=3
3x=3
x=3/3
x = 1
(1,0)
therefore, value of x and y by substitution method is 1 and 0
3x-y=3 -----(1)
9x-3y=9------(2)
x= 3+y / 3
9 ( 3+y / 3) = 9
27+9y /3 = 9
27 +9y = 9*3
9y = 27-27
9y =0
y=0/9
y=0
(put value of y in 1st equation)
3x-y=3
3x-0=3
3x=3
x=3/3
x = 1
(1,0)
therefore, value of x and y by substitution method is 1 and 0
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