Math, asked by abhirajsalesdatia, 4 months ago

solve the equation by trail and error method 2y=10

Answers

Answered by nightread
3

Answer:

Let's assume y = 3

LHS = 2y

= 2 × 3

= 6

RHS = 10

LHS ≠ RHS hence, y ≠ 2

Let's assume that y = 4

LHS = 2y

= 2 × 4

= 8

RHS = 10

LHS ≠ RHS hence, y ≠ 4

Assume that y = 5

LHS = 2y

= 2 × 5

= 10

RHS = 10

LHS = RHS and hence, y = 5.

Hope it helps

Answered by Anonymous
2

Step-by-step explanation:

2y = 10

let y = 0

2 x 0 10

2y = 10

let y = 1

2 x 1 10

2y = 10

let y = 2

2 x 2 10

2y = 10

let y = 3

2 x 3 10

2y = 10

let y = 4

2 x 4 10

2y = 10

let y = 5

2 x 5 = 10

Therefore , y = 5

hope it helps you

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