Question

solve the equation by using method of completing square.... ​

Answer 1

(D) 3x^2-3x+3= 0

solution:- 3x^2-3x+3= 0

3x^2/3-3x/3+3/3 = 0

x^2-x+1 = 0

x^2-x = -1

x^2-x+(x/3)^2 = -1+(x/3)^2

x^2-x+(x/3)^2-(x/3)^2 = -1

x^2-x = -1

x^2-x+1 = 0

Hence proved