solve the equation by using the method of cross multiplication: x+y=7, 5x +12y=7
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Answered by
76
We have two equations as follows :-
1) x + y = 7
2) 5x + 12y = 7
Solving this by cross multiplication :-
First we have to convert the equations into the form of ax + by + c = 0
So,
The two equations are
1) x + y - 7 =0
2) 5x + 12y - 7 = 0
So,
We know the format of cross multiplication that :-
X = b1c2 - b2c1 / a1b2 - a2b1
And,
Y = c1a2 - c2a1 / a1b2 - a2b1
This has been obtaines from the basic formula only.
When we will equate the x one with the constant one and y one with the constant one we will get the same result which i have used.
X = 1*(-7) - 12*(-7) / 1*12 - 5*1
X = -7 + 84 / 12 - 5
X = 77 / 7
X = 11
Again , for obtaining y
Y = (-7)*5 - (-7)*1 / 1*12 - 5*1
Y = -35 + 7 / 12 - 5
Y = -28 / 7
Y = (-4)
Hence,
The answer is x = 11 and y = (-4)
1) x + y = 7
2) 5x + 12y = 7
Solving this by cross multiplication :-
First we have to convert the equations into the form of ax + by + c = 0
So,
The two equations are
1) x + y - 7 =0
2) 5x + 12y - 7 = 0
So,
We know the format of cross multiplication that :-
X = b1c2 - b2c1 / a1b2 - a2b1
And,
Y = c1a2 - c2a1 / a1b2 - a2b1
This has been obtaines from the basic formula only.
When we will equate the x one with the constant one and y one with the constant one we will get the same result which i have used.
X = 1*(-7) - 12*(-7) / 1*12 - 5*1
X = -7 + 84 / 12 - 5
X = 77 / 7
X = 11
Again , for obtaining y
Y = (-7)*5 - (-7)*1 / 1*12 - 5*1
Y = -35 + 7 / 12 - 5
Y = -28 / 7
Y = (-4)
Hence,
The answer is x = 11 and y = (-4)
Answered by
39
hey here is your answer
x=11 y=-4
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