Math, asked by RohillaRajput100, 17 days ago

Solve the equation
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Answered by mahendra15aug
1

(3pqr - 6 {p}^{2}  {q}^{2}  {r}^{2} ) \div 3pq   \\  \frac{3pqr}{3pq}  -  \frac{6 {p}^{2} {q}^{2}  r {}^{2} }{3pq}  \\ r - 2 {p}^{2 - 1}  {q}^{2 - 1}  {r}^{2}  \\ r - 2pqr {}^{2}  = r(1 - 2pqr)

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Answered by vikrantruhela6938
2

This is your correct answer

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