Solve the equation Cos(5x) = 1/SQRT(2). Find value of x in degrees such that 0 degree <x<60 degrees. Answer upto 0 decimal.
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Step-by-step explanation:
Given:-
Cos (5X)=1/√2
To find:-
Find value of x in degrees such that 0 degree <x<60 degrees. Answer upto 0 decimal.
Solution:-
Given that
Cos (5X)=1/√2
We know that 1/√2 is equal to the cosine value of 45°
=>Cos 5X = Cos 45°
=>5X = 45°
Since X is an acute angle
=>X = 45°/5
=>X=9°
Answer:-
The value of X = 9°
Check:-.
If X = 9 then
LHS = Cos(5×9°)
=>Cos 45°
=>1/√2
=>RHS
LHS=RHS is true for X=9°
Used formula:-
- Cos 45°=1/√2
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