Solve the equation cos¹x + sin¹x/2=π/6
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Answer:
Step-by-step explanation:
cos^-1x+sin^-1(x/2)=pie/6
we know cos^-1(x/2)+sin^-1(x/2)=pie/2
so sin^-1(x/2)=pie/2-cos^-1(x/2)
substitute we get
cos^-1(x)-cos^-1(x/2)=pie/6-pie/2
cos^-1(x)-cos^-1(x/2)=-pie/3
cos^-1(x)-cos^-1(x/2)=-cos^-1(1/2)
cos^-1(x)=cos^-1(x/2)-cos^-1(1/2)
A=cos^-1(x/2)
B=cos^-1(1/2)
cosA=x/2
sinA=sqrt(4-x^2)/2
cosB=1/2
sinB=sqrt(3)/2
cos^-1(x)=A-B
x=cos(A-B)
cosAcosB+sinAsinB=x
(x/2)(1/2)+sqrt(4-x^2)/2 * sqrt(3)/2
x/4 +sqrt(3)/4 sqrt(4-x^2)
x-x/4=(3)^1/2/4 *sqrt(4-x^2)
x(3/4)=3^1/2 /4 * sqrt(4-x^2)
3x=root 3 *sqrt(4-x^2)
9x^2=12–3x^2
x^2=1
x=+1 ,x=-1
mark brainliest its the correct ans pal::))
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