solve the equation dy/dx = y cotx, given x=π/2, y= 1.
Answers
Answer:
The solution of the given equation is y = sin x
Step-by-step explanation:
Given equation is:
= y cot x
=> = cot x dx
Integrating both sides, we get,
log y = log |sin x| + c --(i)
It is given that at x = , y = 1
Therefore, on substituting these values, we get,
log 1 = log |sin | + c
=> 0 = 0 + c
=> c = 0
Therefore, equation (i) now becomes,
log y = log |sin x| + 0
=> log y = log |sin x|
Taking antilog both sides,
=> y = sin x
Therefore, the solution of the given equation is y = sin x
Answer:
the solution of given eq is y = sinx
Step-by-step explanation:
Given equation is:
= y cot x
=> = cot x dx
Integrating both sides, we get,
log y = log |sin x| + c --(i)
It is given that at x = , y = 1
Therefore, on substituting these values, we get,
log 1 = log |sin | + c
=> 0 = 0 + c
=> c = 0
Therefore, equation (i) now becomes,
log y = log |sin x| + 0
=> log y = log |sin x|
Taking antilog both sides,
=> y = sin x
Therefore, the solution of the given equation is y = sin x