Question

solve the equation Dy/DX = ycotx ,given X=π/2 or y =1​

Answer 1

Step-by-step explanation:

given, dy/dx=ycotx

then , put value x=π/2 and y=1

then , dy/dx=1cot(π/2)

dy/dx=1(0)

dy/dx=0

Answer 2

Answer:

Hence,the value of dy/dx=ycotx is zero for the given value.

Step-by-step explanation:

Given:

$dy/dx=ycotx$

To find:

dy/dx=ycotx when $x=\pi /2$ or y=1

Solution:

Given, dy/dx=ycotx

or, $dy/y=cotxdx$

Now, integrating both side and derive the value,

∫dy/y=∫cotxdx

or, logy=log mod sinx+c

As we know, log1=0

when y=1, then

or, log 1=log mod sinx

or, log mod sinx=0

Similarly, when x=$\pi /2$ then the given equation can be written as,

or log y=log mod sin\pi /2

or, log y=0

Hence,the value of dy/dx=ycotx is zero for the given value.