solve the equation fast
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sec thita = 13/5
hypotenuse/base = 13/5
let hypotenuse = 13x and base = 5x
perpendicular = √(13x)^2- √(5x)^2
= √144x^2
= 12x
sin thita = perpendicular/hypotenuse
= 12x/13x = 12/13
sin thita = 12/13
Hence proved.
hypotenuse/base = 13/5
let hypotenuse = 13x and base = 5x
perpendicular = √(13x)^2- √(5x)^2
= √144x^2
= 12x
sin thita = perpendicular/hypotenuse
= 12x/13x = 12/13
sin thita = 12/13
Hence proved.
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