Question

Solve the equation, find the value of x
1/3 + 1/x = 3
x=?

Answer 1

Answer:

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If x−

If x− x

If x− x1

If x− x1

If x− x1 =3, find the value of x

If x− x1 =3, find the value of x 3

If x− x1 =3, find the value of x 3 −

If x− x1 =3, find the value of x 3 − x

If x− x1 =3, find the value of x 3 − x 3

If x− x1 =3, find the value of x 3 − x 3

If x− x1 =3, find the value of x 3 − x 3 1

If x− x1 =3, find the value of x 3 − x 3 1

If x− x1 =3, find the value of x 3 − x 3 1 .

a

a 3

a 3 −b

a 3 −b 3

a 3 −b 3 =(a−b)

a 3 −b 3 =(a−b) 3

a 3 −b 3 =(a−b) 3 +3ab(a−b)

a 3 −b 3 =(a−b) 3 +3ab(a−b)Here,

a 3 −b 3 =(a−b) 3 +3ab(a−b)Here,a=x

a 3 −b 3 =(a−b) 3 +3ab(a−b)Here,a=xb=

a 3 −b 3 =(a−b) 3 +3ab(a−b)Here,a=xb= x

a 3 −b 3 =(a−b) 3 +3ab(a−b)Here,a=xb= x1

a 3 −b 3 =(a−b) 3 +3ab(a−b)Here,a=xb= x1

a 3 −b 3 =(a−b) 3 +3ab(a−b)Here,a=xb= x1

a 3 −b 3 =(a−b) 3 +3ab(a−b)Here,a=xb= x1 x

a 3 −b 3 =(a−b) 3 +3ab(a−b)Here,a=xb= x1 x 3

a 3 −b 3 =(a−b) 3 +3ab(a−b)Here,a=xb= x1 x 3 −

a 3 −b 3 =(a−b) 3 +3ab(a−b)Here,a=xb= x1 x 3 − x

a 3 −b 3 =(a−b) 3 +3ab(a−b)Here,a=xb= x1 x 3 − x 3

a 3 −b 3 =(a−b) 3 +3ab(a−b)Here,a=xb= x1 x 3 − x 3

a 3 −b 3 =(a−b) 3 +3ab(a−b)Here,a=xb= x1 x 3 − x 3 1

a 3 −b 3 =(a−b) 3 +3ab(a−b)Here,a=xb= x1 x 3 − x 3 1

a 3 −b 3 =(a−b) 3 +3ab(a−b)Here,a=xb= x1 x 3 − x 3 1 =(x−

a 3 −b 3 =(a−b) 3 +3ab(a−b)Here,a=xb= x1 x 3 − x 3 1 =(x− x

a 3 −b 3 =(a−b) 3 +3ab(a−b)Here,a=xb= x1 x 3 − x 3 1 =(x− x1

a 3 −b 3 =(a−b) 3 +3ab(a−b)Here,a=xb= x1 x 3 − x 3 1 =(x− x1

a 3 −b 3 =(a−b) 3 +3ab(a−b)Here,a=xb= x1 x 3 − x 3 1 =(x− x1 )

a 3 −b 3 =(a−b) 3 +3ab(a−b)Here,a=xb= x1 x 3 − x 3 1 =(x− x1 ) 3

a 3 −b 3 =(a−b) 3 +3ab(a−b)Here,a=xb= x1 x 3 − x 3 1 =(x− x1 ) 3 +3(x−

a 3 −b 3 =(a−b) 3 +3ab(a−b)Here,a=xb= x1 x 3 − x 3 1 =(x− x1 ) 3 +3(x− x

a 3 −b 3 =(a−b) 3 +3ab(a−b)Here,a=xb= x1 x 3 − x 3 1 =(x− x1 ) 3 +3(x− x1

a 3 −b 3 =(a−b) 3 +3ab(a−b)Here,a=xb= x1 x 3 − x 3 1 =(x− x1 ) 3 +3(x− x1

a 3 −b 3 =(a−b) 3 +3ab(a−b)Here,a=xb= x1 x 3 − x 3 1 =(x− x1 ) 3 +3(x− x1 )

a 3 −b 3 =(a−b) 3 +3ab(a−b)Here,a=xb= x1 x 3 − x 3 1 =(x− x1 ) 3 +3(x− x1 ) =(3)

a 3 −b 3 =(a−b) 3 +3ab(a−b)Here,a=xb= x1 x 3 − x 3 1 =(x− x1 ) 3 +3(x− x1 ) =(3) 3

a 3 −b 3 =(a−b) 3 +3ab(a−b)Here,a=xb= x1 x 3 − x 3 1 =(x− x1 ) 3 +3(x− x1 ) =(3) 3 +3(3)

a 3 −b 3 =(a−b) 3 +3ab(a−b)Here,a=xb= x1 x 3 − x 3 1 =(x− x1 ) 3 +3(x− x1 ) =(3) 3 +3(3) =27+9

a 3 −b 3 =(a−b) 3 +3ab(a−b)Here,a=xb= x1 x 3 − x 3 1 =(x− x1 ) 3 +3(x− x1 ) =(3) 3 +3(3) =27+9 =36

a 3 −b 3 =(a−b) 3 +3ab(a−b)Here,a=xb= x1 x 3 − x 3 1 =(x− x1 ) 3 +3(x− x1 ) =(3) 3 +3(3) =27+9 =36Hence, the required answer is 36.

Answer 2

Answer:

3/8

Step-by-step explanation:

1/3 + 1/x = 3

1/x = 3 - 1/3

1/x = 8/3

1 = 8/3x

x = 3/8

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