Question

solve the equation for 'x',9x^2-9(a+b)x+(2a^2+5ab+2b^2)=0

Answer 1

${9x}^{2} - 9(a + b)x + ( {2a}^{2} + 5ab + {2b}^{2} ) = 0 \\ {9x}^{2} - 3(3a + 3b)x + ( {2a}^{2} + 4ab + ab + {2b}^{2} ) = 0 \\ {9x}^{2} - 3 ((a + 2b) + (2a + b))x + (2a(a + 2b) + b(a + 2b)) = 0 \\ 9 {x}^{2} - 3(a + 2b)x - 3(2a + b)x + ((a + 2b)(2a + b)) = 0 \\ 3x(3x - (a + 2b)) - (2a + b)(3x - (a + 2b)) = 0 \\ (3x - (a + 2b))(3x - (2a + b)) = 0$
$3x = a + 2b \: \: \: \: \: or \: \: \: \: \: 2a + b \\ x = \frac{a + 2b}{3} \: \: \: \: \: or \: \: \: \: \: \frac{2a + b}{3}$
If it helped you, please mark the answer as the Brainliest. Please!