Question

Solve the equation for x and also verify the values of x found:
tan^-1 (2x) + tan^-1 (3x)= n$\pi$ + 3$\pi$ /4

Answer 1

tan-1(2x) + tan-1(3x) = nπ + 34 3 π 4 Take LHS tan-1(2x) + tan-1(3x) = nπ + 34 3 π 4 We know that, Formula Since, x = -16 1 6 ∈(−16‾√,16‾√) ( − 1 6 , 1 6 ) So, x = -16 1 6 is the root of the given equation Therefore, x = -16