Question

Solve the equation for x. log x - 1\2 Log 2 = 1\2log(3x -4)​

Answer 1

Answer:

{2, 4}

Step-by-step explanation:

log x - 1\2 Log 2 = (1\2)log(3x - 4)​

log x - log $2^{\frac{1}{2}}$ = log $(3x-4)^{\frac{1}{2} }$

log $\frac{x}{2^{1/2} }$ =  log $(3x-4)^{\frac{1}{2} }$

( $\frac{x}{2^{1/2} }$ )² = [$(3x-4)^{\frac{1}{2} }$ ]²

x² / 2 = 3x - 4

x² - 6x + 8 = 0 ⇔ (x - 2)(x - 4) = 0

$x_{1}$ = 2 and $x_{2}$ = 4

{2, 4}

Answer 2

Answer:

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