Math, asked by srinivasaraoburagama, 1 month ago

Solve the equation
given by y=x3 in x,dy/DX is
A) 3x² inx
B) 3x² in x + x2
c) x2
D) 3x​

Answers

Answered by sreeragh32
0

Answer:

B) 3x² ln x + x²

Step-by-step explanation:

Hello!

Differentiation is super fun once you understand how it works!

Your question: x³ Ln x

dy/dx = d(x³ Ln x)/dx

There are two functions, x³ and Ln x

Usually, if u and v are two functions in terms of x,

 \frac{d(uv)}{dx}  =  u\frac{dv}{dx}  + v \frac{du}{dx}

So, let's apply that here

 \frac{d( {x}^{3} ln \: x)}{dx}  =  {x}^{3} \frac{d(ln \: x)}{dx}  + ln \: x \frac{d( {x}^{3} )}{dx} \\ =  ({x}^{3}  \times  \frac{1}{x}  \: ) +  (\: ln \: x \times 3 {x}^{2} ) \\  =  {x}^{2}  + 3 {x}^{2} ln \: x

Hence, option B

______________________

Hope that helps!

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