solve the equation h/5-5/7=2/3
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given,
h/5-5/7=2/3
if we transfer -5/7 towards the R.H.S SIDE
THEN,
h/5 = 2/3+5/7
the common factor of 3 and 7 is 21
therefore,
h/5 = 2/3×7/7+5/7×3/3
= 14/21+15/21
= 14+15/21
= 29/21
h= 29/21×5
h= 29/105
h= 5.8/21= 0.825/3 .....
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