Solve the equation :- i) 3 (n-5) = 21 , ii) 4 = 5 (P-2)
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3
1)3n-15=21
3n=36
n=12...
2)4=5p-10
5p=14
P(14/5
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0
1. 3 (n-5)=21
3n-15=21
3n=21+15
3n=36
n=36÷3
n=12.
2. 4=5(p-2)
4=5p-10
4+10=5p
14=5p
14÷5=p
2.8=p
HOPE IT HELPS YOU
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