Solve the equation, if possible. Determine whether the equation has one solution, no solution, or infinitely many solutions.
1.) 7y+13=5y-3
2.) 8+9p=9p-7
3.) 3(7r-2)=21r-6
4.) 2(3x+6)=3(2x-6)
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1) 7y+13 = 5y - 3
7y-5y = -13 -3
2y = -10
y = -10÷2
y = -5
2 ) no solution
3) no solution
4 ) no solution
in second equation 9p and 9p will cancel each other
in third equation 21r and 21r will cancel each other
in fourth equation 6x and 6x will cancel each other
7y-5y = -13 -3
2y = -10
y = -10÷2
y = -5
2 ) no solution
3) no solution
4 ) no solution
in second equation 9p and 9p will cancel each other
in third equation 21r and 21r will cancel each other
in fourth equation 6x and 6x will cancel each other
brooklynnmurphy17:
So does the first one have a solution or no?
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