solve the equation log(x+3)+log(x-3)=16
Answers
Answered by
1
ur answer is
{x-3}-{x+3}=16
2
x - 9=16
x=0+5
x=5
{x-3}-{x+3}=16
2
x - 9=16
x=0+5
x=5
Answered by
2
Log(a) + Log(b) = Log(a*b)
therefore
Log((x+3)*(x-3))=16
x^2 - 9=16
x^2 =25
x = 5
therefore
Log((x+3)*(x-3))=16
x^2 - 9=16
x^2 =25
x = 5
Similar questions