Question

solve the equation of 2/5x-2= 5-3/5x​

Answer 1

Answer:

to find x = ?

when,

|x2+3x+5|+x2+3x+5=0−−−−−−−(1)|x2+3x+5|+x2+3x+5=0−−−−−−−(1)

Let, x2+3x+5=φx2+3x+5=φ

Now, (1)(1)becomes,

|φ|+φ=0|φ|+φ=0

We know that,

|φ|=±φ|φ|=±φ

This means, we have two scenarios,

−φ+φ=0−−−−−−−−−−−−−−(2)−φ+φ=0−−−−−−−−−−−−−−(2)

and,

φ+φ=0−−−−−−−−−−−−−−−(3)φ+φ=0−−−−−−−−−−−−−−−(3)

Now,

Equation (2) gives, φ=φφ=φ

This is rather insignificant.

Equation (3) gives, 2φ=02φ=0

⟹φ=0———————————−(4)⟹φ=0———————————−(4)

Thus,

x2+3x+5=0x2+3x+5=0from(4)

Now, using the Quadratic Formula,

x=−b±b2−4ac√2ax=−b±b2−4ac2a

Here, a = 1, b = 3 and c = 5,

substituting the values we will get −3±i11√2

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Answer 2

Answer:

$\frac{2}{5x } - 2 =5 - \frac{3}{5x} \\ \frac{2}{5x} + \frac{3}{5x} = 5 + 2 \\ \frac{5}{5x} = 7 \\ \frac{1}{x} = \frac{7}{1} \\ 7x = 1 \\ x = \frac{1}{7}$

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