solve the equation of 2x/3+1=7/3
Answers
Step-by-step explanation:
How to solve your problem
2
3
+
1
=
7
3
\frac{2x}{3}+1=\frac{7}{3}
32x+1=37
Solve
1
Find common denominator
2
3
+
1
=
7
3
\frac{2x}{3}+1=\frac{7}{3}
32x+1=37
2
3
+
3
3
=
7
3
\frac{2x}{3}+\frac{3}{3}=\frac{7}{3}
32x+33=37
2
Combine fractions with common denominator
2
3
+
3
3
=
7
3
\frac{2x}{3}+\frac{3}{3}=\frac{7}{3}
32x+33=37
2
+
3
3
=
7
3
\frac{2x+3}{3}=\frac{7}{3}
32x+3=37
3
Multiply all terms by the same value to eliminate fraction denominators
2
+
3
3
=
7
3
\frac{2x+3}{3}=\frac{7}{3}
32x+3=37
3
(
2
+
3
3
)
=
3
⋅
7
3
3(\frac{2x+3}{3})=3 \cdot \frac{7}{3}
3(32x+3)=3⋅37
4
Cancel multiplied terms that are in the denominator
3
(
2
+
3
3
)
=
3
⋅
7
3
3(\frac{2x+3}{3})=3 \cdot \frac{7}{3}
3(32x+3)=3⋅37
2
+
3
=
3
⋅
7
3
2x+3=3 \cdot \frac{7}{3}
2x+3=3⋅37
5
Multiply the numbers
2
+
3
=
3
⋅
7
3
2x+3={\color{#c92786}{3}} \cdot {\color{#c92786}{\frac{7}{3}}}
2x+3=3⋅37
2
+
3
=
7
2x+3={\color{#c92786}{7}}
2x+3=7
6
Subtract
3
3
3
from both sides of the equation
2
+
3
=
7
2x+3=7
2x+3=7
2
+
3
−
3
=
7
−
3
2x+3{\color{#c92786}{-3}}=7{\color{#c92786}{-3}}
2x+3−3=7−3
7
Simplify
Subtract the numbers
Subtract the numbers
2
=
4
2x=4
2x=4
8
Divide both sides of the equation by the same term
2
=
4
2x=4
2x=4
2
2
=
4
2
\frac{2x}{{\color{#c92786}{2}}}=\frac{4}{{\color{#c92786}{2}}}
22x=24
9
Simplify
Cancel terms that are in both the numerator and denominator
Divide the numbers
=
2
x=2
x=2
Show less
Solution
=
2
Answer:
2x/3=7/3-1
2x/3 = 4/3
2x = 4/3 × 3
2x = 4
x = 4/2
x=2
Step-by-step explanation:
take 1 on otherside (7/3)
Taking lcm of 7/3 and 1
answer = 4/3
then bring 3 on other side which was dividing but will then multiply
Then cuttings
now 4/2 answer then again cuttings
answer = 2
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