Question

solve the equation . please yrr​

Answer 1

Answer:

-11

Step-by-step explanation:

x'2-x'2-2x+2x+4=x+3/2

+4(2)=x+3

+8-3=x

x=+5

Mark me BRAINLIEST please

Answer 2

QUESTION :

$\dfrac{ {x}^{2} \: - \: (x + 2)( \times - 2) }{x + 3} = \: \dfrac{1}{2}$

ANSWER : x = 5

Identity used : (a-b)(a+b) = a² - b²

Solution :

(x+2)(x-2) = x² - (2)² = x² - 4

$\sf \implies \: \dfrac{ {x}^{2} \: - \: (x + 2)( x - 2) }{x + 3} = \dfrac{1}{2} \\ \\ \sf \implies \: \dfrac{ {x}^{2} - \: ( {x}^{2} \: - 4 \: ) }{x + 3} \: = \: \dfrac{1}{2} \\ \\ \implies \sf \dfrac{ {x}^{2} \: - \: {x}^{2} \: + 4}{x + 3} \: = \dfrac{1}{2} \\ \\ \implies \sf \dfrac{4}{x + 3} = \: \dfrac{1}{2}$

on cross multiplying, we get ;

=> 4×2 = 1×(x+3)

=> 8 = x + 3

=> x = 8 - 3

=> x = 5