Question

solve the equation pls

Answer 1

x⁴-2x³-5x²+6x+8=0
step 1: Factor left side of equation.
(x+1)(x-2)(x²-x-4)=0
step 2:set factor equal to 0.
x+@=0 or x-2=0 or x²-x-4=0
answer
x= -1 or x= 2 or x = 2.5615528128088303 or x= -1.5615528128088303

Answer 2

jix(x-1)(x+2)(x-3)+8=0,

(x²-x)(x²-x-6)+8=0,

now let (x²-x)=A,

then the equation becomes

A (A-6)+8=0,

A²-6A+8=0,

A²-(4+2)A+8=0,

A²-4A-2A+8=0,

A(A-4)-2(A-4)=0,

(A-4)(A-2)=0,

if
A-4=0,

then

x²-x-4=0,
now solve it by quadratic formula,

and if A-2=0,

then
x²-x-2=0,

x²-(2-1)x-2=0,

x²-2x+x-2=0,

x(x-2)+1(x-2)=0,

(x-2)(x+1)=0,

so here if (x-2)=0,

then
x=2,

and if (x+1)=0,

then
x=-1