Solve the equation root 2 X square + X + root 2 is equal to zero
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answer for x= -1-under root1-8root2/4
and -1+under root 1-2troot8/4
i hope if u like comment thanks
and -1+under root 1-2troot8/4
i hope if u like comment thanks
Answered by
0
Answer:
Step-by-step explanation:
The above equation is the form of Ax^2+Bx+c=0.
a=root2x^2,b=1,c=root2
X=-b^2+-root b square-4×a×c/2a
X=(-1)+-root (1)^2-4×root2×root2/2×root2
=(-1)+- root 1-4×2/2root2
=(-1)+-root 1-8/2root2
=-1+-root-7/2root2
=-1+-root-1 ×7/2root2. (Root-1=i)
=-1+root7i/2root2
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