Math, asked by johnngulube9, 6 months ago

Solve the equation √s+1÷s-1=2

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Answered by sakshisingh27

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The first term is, 2s2 its coefficient is 2 .

The middle term is, +s its coefficient is 1 .

The last term, "the constant", is -1

Step-1 : Multiply the coefficient of the first term by the constant 2 • -1 = -2

Step-2 : Find two factors of -2 whose sum equals the coefficient of the middle term, which is 1 .

-2 + 1 = -1

-1 + 2 = 1 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -1 and 2

2s2 - 1s + 2s - 1

Step-4 : Add up the first 2 terms, pulling out like factors :

s • (2s-1)

Add up the last 2 terms, pulling out common factors :

1 • (2s-1)

Step-5 : Add up the four terms of step 4 :

(s+1) • (2s-1)

Which is the desired factorization

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