Question

solve the equation Sec? 2x = 1- tan 2x​

Answer 1

Answer:

sec 2

2x=1−tan2x 1+tan 2/ 2x=1−tan2x tan 2

2x+tan2x=0

tan2x(tan2x+1)=0

tan2x=0 or tan2x+1=0

Now, tan2x=0

tan2x=tan0

2x=nπ+0,n∈Z x= 2nπ,n∈Z

tan2x+1=0

tan2x=−1=−tan 4π

=tan(π− 4π )=tan 4\3π

2x=nπ+ 4\3π ,n∈Z

x= 2nπ + 8/3π ,n∈Z

Therefore, the general solution is 2nπ or 2nπ + 8/3π ,n∈Z

Step-by-step explanation:

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