Solve the equation (sec A-2)(tan 3A-1)=0, when 0°<A <90°
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Answer:
A = 15° , 60° , 75° are the solution
Step-by-step explanation:
Solve the equation (sec A-2)(tan 3A-1)=0
(sec A-2) = 0
=> secA - 2 = 0
=> secA = 2
=> 1/CosA = 2
=> 2CosA = 1
=> CosA = 1/2
=> A = 60°
tan 3A-1 = 0
=> tan3A = 1
=> 3A = 45° or 225°
=> A = 45° /3 or 225°/3
=> A = 15° or 75°
A = 15° , 60° , 75° are the solution
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