Solve the equation
Sin 2Q = sin Q
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Answer:
nahi pata ha bhai please find the attachment of the answer is
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Step-by-step explanation:
Explanation:
sin2(θ)=12
sin(θ)=1√2=√22orsin(θ)=−1√2=−√22
θ=π4+2kπorθ=3π4+2kπor
θ=5π4+2kπorθ=7π4+2kπ
If you trace these four solutions in the trigonometrical circle you will see that the four can be resumed in just one:
θ=π4+kπ2
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